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A couple of songs from Rodrigo y Gabriela ("Stairway to Heaven", and "Hanuman") to get everyone energized for the upcoming 3-day weekend.

I got a little (a lot) carried away while I was putting the notes from Wednesday's class online. About half of the notes were material we covered in class, the remaining material was new. We spent 10 minutes or so looking back at some of the new matierial.

Part of the reason for adding so much material to the Wednesday notes was to finish that first block of material so that we could start something new in class today.

Now that we've learned something about the composition of the atmosphere we will be learning about some of its other physical properties such as temperature, air density, and air pressure. We'll also be interested in how they change with altitude.

Two bottles, one containing mercury the other an equal volume of water, were passed around class. Even though the volumes were the same, the masses, weights, and densities were very different.

Other books will define mass as inertia or as resistance to change in motion (this comes from Newton's 2nd law of motion, we'll cover that later in the semester). The next picture illustrates both definitions.

A Cadillac and a volkswagen
have both stalled in an intersection. Both cars are made of
steel. The Cadillac is larger and has more steel, more stuff,
more mass. The Cadillac would be much harder to get moving than
the VW, it has
a larger inertia (it would also be harder to slow down and stop once it
is
moving).

The bottle of mercury that made its way through class (thanks for returning the mercury) weighed more than the water. That was something you could feel.

Here are a couple of questions that I asked in class.

We assume that all three objects are here on the earth.

To determine the weight you multiply the mass by the gravitational acceleration. Since all three objects have the same mass and g is a constant you get the same weight for each object. That's why we use mass and weight interchangeably on the earth. Here was a follow up question:

Imagine carrying a brick from the earth to the moon. It would be the same brick in both cases and would have the same mass. The value of the gravitational acceleration on the moon is about 1/6th the value on the earth. So a brick that weighed 5 pounds on the earth would weigh less than 1 pound on the moon. The brick would weigh almost 12 pounds on the surface on Jupiter.

Here's a little more information (not covered in class) about what determines the value of the gravitational acceleration (Newton's Law of Universal Gravitation).

Density is the next term we need to look at.

In
the first example there is more mass (more dots, which symbolize air
molecules) in the right box than
in the left box. Since the two volumes are equal the box at right
has higher density. Equal masses are squeezed into different
volumes in the bottom example. The box with smaller volume has
higher density. Mercury
is more than 10 times more dense than water.

The air that surrounds the earth has mass. Gravity pulls downward on the atmosphere giving it weight. Galileo conducted (in the 1600s) a simple experiment to prove that air has weight. The experiment wasn't mentioned in class.

Atmospheric pressure depends on, is determined by, the weight of the air overhead. This is one way, a sort of large scale representation, of understanding air pressure.

Under normal conditions a 1 inch by 1 inch column of air stretching from sea level to the top of the atmosphere will weigh 14.7 pounds. Normal atmospheric pressure at sea level is 14.7 pounds per square inch (psi, the units you use when you fill up your car or bike tires with air).

The iron bar sketched below was passed around class today. You were supposed to estimate it's weight.

It also weighs 14.7 pounds. When you stand the bar on end, the pressure at the bottom would be 14.7 psi.

So the weight of a 1" x 1" steel bar 52 inches long is the same as a 1" x 1" column of air that extends from sea level to the top of the atmosphere 100 or 200 miles (or more) high. The pressure at the bottom of both would be 14.7 psi.

Psi are perfectly good pressure units, but they aren't the ones that most meteorologists used.

Typical sea level pressure is 14.7 psi or about 1000 millibars (the units used by meterologists and the units that we will use in this class most of the time) or about 30 inches of mercury (refers to the reading on a mercury barometer, we'll cover mercury barometers on Friday, they're used to measure pressure). Milli means 1/1000 th. So 1000 millibars is the same as 1 bar. You sometimes see typical sea level pressure written as 1 atmosphere.

Mercury (13.6 grams/cm

You never know whether something you learn in NATS 101 (or ATMO 170A1 as it's now called) will turn up. I lived and worked for a short time in France (a very enjoyable and interesting period in my life). Here's a picture of a car I owned when I was there (this one is in mint condition, mine was in far worse shape)

It's a Peugeot 404. After buying it I took it to the service station to fill it with gas and to check the air pressure in the tires. I was a little confused by the air compressor though, the scale only ran from 0 to 3. I'm used to putting 30 psi or so in my car tires (about 90 psi in my bike tires). After staring at the scale for a while I finally realized the numbers were pressures in "bars" not "psi". Since 14.7 psi is equivalent to 1 bar, 30 psi would be about 2 bars. So I filled up all the tires and carefully drove off (one thing I quickly learned was you have to watch out for in France is the "Priority to the right" rule).

The following material wasn't covered in class. I'll probably review it before the Practice Quiz next Wednesday

You can learn a lot about pressure from bricks.

For example the photo below (taken in my messy office) shows two of the bricks from class. One is sitting flat, the other is sitting on its end. Each brick weighs about 5 pounds. Would the pressure at the base of each brick be the same or different in this kind of situation?

Pressure is determined by (depends on) weight so you might think the pressures would be equal. But pressure is weight divided by area. In this case the weights are the same but the areas are different. In the situation at left the 5 pounds must be divided by an area of about 4 inches by 8 inches = 32 inches. That works out to be about 0.15 psi. In the other case the 5 pounds should be divided by a smaller area, 4 inches by 2 inches = 8 inches. That's a pressure of 0.6 psi, 4 times higher. Notice also these pressures are much less the 14.7 psi sea level atmospheric pressure.

The main reason I brought the bricks was so that you could understand what happens to pressure with increasing altitude. Here's a drawing of the 5 bricks stacked on top of each other.

The atmosphere is really no different. Pressure at any level is determined by the weight of the air still overhead. Pressure decreases with increasing altitude because there is less and less air remaining overhead.

At sea level altitude, at Point 1, the pressure is normally about 1000 mb. That is determined by the weight of all (100%) of the air in the atmosphere.

Some parts of Tucson, at Point 2, are 3000 feet above sea level (most of central Tucson is a little lower than that around 2500 feet). At 3000 ft. about 10% of the air is below, 90% is still overhead. It is the weight of the 90% that is still above that determines the atmospheric pressure in Tucson. If 100% of the atmosphere produces a pressure of 1000 mb, then 90% will produce a pressure of 900 mb.

Pressure is typically about 700 mb at the summit of Mt. Lemmon (9000 ft. altitude at Point 3) and 70% of the atmosphere is overhead..

Pressure decreases rapidly with increasing altitude. We will find that pressure changes more slowly if you move horizontally. Pressure changes about 1 mb for every 10 meters of elevation change. Pressure changes much more slowly normally if you move horizontally: about 1 mb in 100 km. Still the small horizontal changes are what cause the wind to blow and what cause storms to form.

Point 4 shows a submarine at a depth of about 30 ft. or so. The pressure there is determined by the weight of the air and the weight of the water overhead. Water is much denser and much heavier than air. At 30 ft., the pressure is already twice what it would be at the surface of the ocean (2000 mb instead of 1000 mb).